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28x+x^2=1.040
We move all terms to the left:
28x+x^2-(1.040)=0
We add all the numbers together, and all the variables
x^2+28x-(1.04)=0
We add all the numbers together, and all the variables
x^2+28x-1.04=0
a = 1; b = 28; c = -1.04;
Δ = b2-4ac
Δ = 282-4·1·(-1.04)
Δ = 788.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-\sqrt{788.16}}{2*1}=\frac{-28-\sqrt{788.16}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+\sqrt{788.16}}{2*1}=\frac{-28+\sqrt{788.16}}{2} $
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